Question #97827
1. Calculate the de Broglie wavelength, in meters, of a 5500-lb sport-utility vehicle moving at 57 miles per hour.

2. Calculate the wavelength (in nanometers) associated with a positron moving at 5.8 × 104 m/s. The mass of a positron is 9.11 × 10-31 kg.

3. What is the maximum number of orbitals that can be identified with the following quantum numbers: n = 3, ℓ = 2?
a. 7
b. 5
c. 8
d. 18
e. 10
1
Expert's answer
2019-11-05T07:39:28-0500

λ=h/p\lambda=h/p

h=6.626×1034Jsh=6.626×10^{-34}J-s

h=6.626×1034×2.205×6.21×104×3600lb.(mile)2/hrh=6.626×10^{-34}×2.205×6.21×10^{-4}×3600lb.(mile)^2/hr

m=5500lbm=5500 lb

v=57miles/hrv=57miles /hr

p=m×v=5500×57lb.mile/hrp=m×v=5500×57 lb.mile/hr

p=313500lb.(mile)/hrp=313500lb.(mile)/hr

λ=32.663×1034/313500m\lambda=32.663×10^{-34}/313500 m

λ=1.042×1038m\lambda=1.042×10^{-38} m (answer)

2.m=9.11×1031kgm=9.11×10^{-31}kg

v=5.8×104m/sv=5.8×10^4m/s

mv=9.11×1031×5.8×104kg.m/smv=9.11×10^{-31}×5.8×10^4kg.m/s

mv=52.838×1027kg.m/smv=52.838×10^{-27}kg.m/s

λ=h/p\lambda=h/p

λ=6.626×1034/52.838×1027m\lambda=6.626×10^{-34}/52.838 ×10^{-27}m

λ=1.254×108m\lambda=1.254×10^{-8}m

λ=12.54nm\lambda=12.54nm (answer)

3.n=3n=3

l=2l=2

Subshell - 3d

The subshell 3d contains 5 orbitals and each orbital contains 2 electrons.

(b)----answer














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