Q97354
Solution:
The law of multiple proportions states that: If two elements form more than one compound between them, then the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers. ---(1)
So, let us denote the unknown metal as "M" and let it's two oxides have formulas "MO_x" and "MO_y" .
"\\therefore MO_x" and "MO_y" contain 92.59% and 96.15% of the metal "M" respectively. (given) ---(2)
Let us assume the atomic weight of the metal "M" to be "'p'gms."
Thus, molecular weight of "MO_x=(p+16x)gms."
And molecular weight of "MO_y=(p+16y)gms."
"M+ xO\\to MO_x"
"\\implies 1 mol" or "'p'gms." of the metal reacts with "16x gms." of Oxygen. ---(3)
"M+ yO\\to MO_y"
"\\implies 1 mol" or "'p'gms." of the metal reacts with "16y gms." of Oxygen. ---(4)
From (1), (2) and (3);
For the given facts to agree with the Law of Multiple Proportions, we need to show that for a fixed amount of the metal "('p' gms.)" , the ratio of Oxygen masses in the two oxides is a whole number.
"i.e." "(16x)\/(16y)\\iff (x\/y)" is a whole number.
(2)"\\implies" "p\/(p+16x)=92.59" %
"\\implies 1\/(1+(16x\/p))=0.9259"
"\\implies 16x\/p=(0.9259)^{-1}-1" ---(5)
And,"\\implies p\/(p+16y)=96.15" %
"\\implies 1\/(1+(16y\/p))=0.9615"
"\\implies 16y\/p=(0.9615)^{-1}-1" ---(6)
Dividing (5) by (6), we get;
"x\/y=(0.0741*0.9615)\/(0.9259*0.0385)"
"=2" (Answer)
The ratio x/y is 2, which is a whole number.
Hence Proved.
Thus, the given facts agree with the Law of Multiple Proportions.
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