Nitrogen has an atomic mass of 14.0067 u.
Let one of its isotope having atomic mass 14.003 u has natural abundance of x %.
Other isotope having atomic mass 15.001 u has natural abundance of (100-x) %.
(x×14.003+(100−x)×15.001)/100=14.0067
14.003x+1500.1−15.001x=1400.67
0.998x=99.43
x=99.43/0.998
x=99.629
100−x=0.371
Relative abundance of isotope having atomic mass 14.003 is 99.629 %(Ans)
The other isotope has abundance of 0.371 %(ans)
Comments