Nitrogen has an atomic mass of 14.0067 u.
Let one of its isotope having atomic mass 14.003 u has natural abundance of x %.
Other isotope having atomic mass 15.001 u has natural abundance of (100-x) %.
"(x\u00d714.003 + (100-x)\u00d7 15.001)\/100 =14.0067"
"14.003x +1500.1 -15.001x = 1400.67"
"0.998x=99.43"
"x = 99.43\/0.998"
"x = 99.629"
"100-x =0.371"
Relative abundance of isotope having atomic mass 14.003 is 99.629 %(Ans)
The other isotope has abundance of 0.371 %(ans)
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