Question

If 7.97 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?

C5H12 + 8O2 ⟶ 6H2O + 5CO2

Answer 1

The balanced equation for considered reaction can be written as follows

$C_5H_{12} + 8 O_2 \rightarrow 6 H_2O + 5 CO_2$

$\frac{\nu(C_5H_{12})}{n(C_5H_{12})} = \frac{\nu(CO_2)}{n(CO_2)}$

where $\nu$ - amount of the substance, $n$ - number of the substance molecules within the balanced equation.

$\nu(CO_2)=\frac{\nu(C_5H_{12}) \cdot n(CO_2)}{n(C_5H_{12})}$

$\nu(CO_2)=\frac{7.97 \cdot 5}{1} = 39.75 \; mol$

Answer: 39.75 mol.