The balanced equation for considered reaction can be written as follows
"C_5H_{12} + 8 O_2 \\rightarrow 6 H_2O + 5 CO_2"
"\\frac{\\nu(C_5H_{12})}{n(C_5H_{12})} = \\frac{\\nu(CO_2)}{n(CO_2)}"
where "\\nu" - amount of the substance, "n" - number of the substance molecules within the balanced equation.
"\\nu(CO_2)=\\frac{\\nu(C_5H_{12}) \\cdot n(CO_2)}{n(C_5H_{12})}"
"\\nu(CO_2)=\\frac{7.97 \\cdot 5}{1} = 39.75 \\; mol"
Answer: 39.75 mol.
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