Answer to Question #95842 in General Chemistry for ...

Question

Gaseous butane will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 4.1 g of butane is mixed with 4.37 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

      0.1366mol             Xmol

2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O

             13mol                10mol

n(C₄H₁₀) = m(C₄H₁₀)/M(C₄H₁₀) = 4.1g/58g/mol = 0.0707 mol (excess).

n(O₂) = m(O₂)/M(O₂) = 4.37g/32g/mol = 0.1366 mol (deficiency).

n(H₂O) = X = (0.1366 × 10 / 13) mol = 0.1051 mol.

m(H₂O) = n(H₂O) × M(H₂O) = 0.1051 mol × 18 g/mol = 1.8918 g ≈ 1.89 g.