Question

A 50.00 -g sample of metal at 78.0°c is dropped into cold water. If the metal sample cools to 17.0°c and the specific heat of metal is 0.108 cal/g.°c how much heat is released?

Answer 1

Heat released by metal = $q=m_mc_m(T_2-T1)$

$m_m=50\ g\\c_m=0.108\ cal\ g^{-1}\ \degree C^{-1}\\q=50\times0.108(17-78)=-329.4\ calorie$

Here minus sign indicate that heat is released