Answer to Question #94109 in General Chemistry for Latiyah Timothy

Question

9) Six litres of 0.4M 3-(N-morpholino) propane sulfonic acid (MOPS) buffer of pH 7.8 are required. Available in the laboratory are 10M HCl and 10M NaOH and the basic form of MOPS (M.Wt = 210.3). The pKa for the MOPS zwitterion is 7.2. Describe, showing the relevant calculations, the procedure for preparing the buffer

Answer 1

The pH of this buffer should be calculated with the following expression:

$pH=pK_a+lg(\frac{C_{BA}}{C_{HA}})$, MOPS is a middle strength acid (pKa = 7.2)

We can easily extract the required relation from the formula:

$\frac{C_{BA}}{C_{HA}}=10^{pH-pK_a}=10^{7.8-7.2}=3.98$

On the other hand, the required concentration of the buffer is 0.4M:

$C_{BA}+C_{HA}=0.4$

Now, we can calculate the required concentrations of MOPS and its Na-salt:

$3.98C_{HA}+C_{HA}=0.4$

$C_{HA}=\frac{0.4}{3.98+1}=0.08M$

$C_{BA}=0.4-C_{HA}=0.32M$

$n(HA)=C_{HA}*V_{sol}=0.08M*6L=0.48mol$

$n(BA)=C_{BA}*V_{sol}=0.32M*6L=1.92mol$

$n(HA)+n(BA)=0.48mol+1.92mol=2.40mol$

Now you take 2.40mol*209.3g/mol = 502g of MOPS and 1.92mol/10M = 0.192L of 10M solution of NaOH (react in a 1 to 1 molar relation):

C₇H₁₅NO₄S + NaOH = C₇H₁₄NO₄SNa + H₂O

After the reaction is complete, you dissolve this mixture up to 6L in a special flask with distilled water.