Answer to Question #92215 in General Chemistry for harris

Question

For the following reaction, 4.82 grams of chlorine gas are mixed with excess bromine . The reaction yields 10.4 grams of bromine monochloride .

What is the theoretical yield of bromine monochloride ?

What is the percent yield for this reaction ?

Answer 1

Cl₂ + Br₂ = 2 BrCl

moles of chlorine gas:

$n = \frac {m}{MW} = \frac {4.82 g}{71.0 g/mole} =0.0679 moles$

moles of bromine monochloride:

$0.0679 \cdot \frac {2 mole} {1 mole}=0.136 moles$

theoretical mass of bromine monochloride:

$m= n \cdot MW = 0.136 \cdot 115.5 =15.7 g$

theoretical yield:

$E= \frac {m (practical)} {m (theoretical)} \cdot 100 \% = \frac {10.4 g} {15.7} \cdot 100 \% = 66.3 \%$