Question

How many moles of NaOH are there in 50cm^3 of a solution that has a molarity of 1.76?

Answer 1

Given:

$V(NaOH) = 50cm^3 = 50mL = 0.05L$

$c(NaOH)=1.76 \frac{mol}{L}$

According to the equation of molar concentration, $c(NaOH)=\frac{n(NaOH)}{V(NaOH)}$

Thus, amount of NaOH in moles:

$n(NaOH)=c(NaOH) \cdot V(NaOH) = 1.76\frac{mol}{L}\cdot0.05L=0.088mol$