Answer to Question #91842 in General Chemistry for jimbo

Question

A chemist requires 0.250 mol Na2CO3 for a reaction. How many grams does this correspond to?

Answer 1

M (Na₂CO₃) = 2 × 23 + 12 + 3 × 16 = 106 g mol^-1

m (Na₂CO₃) = 0.250 × 106 = 26.5 g