Answer to Question #91836 in General Chemistry for jimbo

General Chemistry

Question #91836

How many moles of potassium dihydrogen phosphate (KH2PO4) are in
67.9
67.9
g of the compound

Expert's answer

m (KH2PO4)=67, 9 g

n(KH2PO4)-?

n(KH2PO4)= m(KH2PO4)/ M(KH2PO4)=67,9/136.086=0.499 mol≈0,5 mol

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