Answer to Question #91836 in General Chemistry for jimbo

Question

How many moles of potassium dihydrogen phosphate (KH2PO4) are in
67.9
67.9
g of the compound

Answer 1

m (KH2PO4)=67, 9 g

n(KH2PO4)-?

n(KH2PO4)= m(KH2PO4)/ M(KH2PO4)=67,9/136.086=0.499 mol≈0,5 mol