That is, the ratio of ethine С2Н2 to oxygen O2 is 2 to 5, or 1 to 2.5
2.According to the condition, the ethin C2H2 to oxygen O2 ratio 16 : 25, or 1 : 1.5625.
Therefore, ethine C2H2 is in excess, we calculate on oxygen O2.
3.Consider the ratio of oxygen O2 to carbon dioxide CO2:
"n(CO_2) = (25\/5)*4 = 20 (mol)"
Answer: 20 mol
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