The equivalence of this reaction is:
2moles of H2O2↔2moles ofH2O↔1mole of O2↔−196KJ2 moles \space of \space H_2O_2 \leftrightarrow 2 moles \space of H_2O \leftrightarrow 1 mole \space of \space O_2 \leftrightarrow -196 KJ2moles of H2O2↔2moles ofH2O↔1mole of O2↔−196KJ
To determine the energy changed thermochemical equation is used:
4moles of H2O2⋅−196KJ2moles of H2O2=−392 KJ4 moles \space of \space H_2O_2 \cdot \frac {-196 KJ}{2 moles \space of \space H_2O_2} = -392 \space KJ4moles of H2O2⋅2moles of H2O2−196KJ=−392 KJ
Answer: the reaction gives off -392 KJ of heat.
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