Since C= 48.63 %, thus no. of carbon atoms can be calculated as 48.63/12= 4.05
Similarly, for H = 8.18/1 = 8.18
For Oxygen (100-48.63-8.18)/16 = 2.69
Thus, the formula becomes C4.05H8.18O2.69
Thus, dividing each entity by 2.69 The formula becomes: C1.5H3.0O1 (Empirical Formula)
Multiplying above formula by 2 to get whole number ratio gives: C3H6O2 (molecular formula)
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