%O=100%−(48.63%+8.18%)=43.19%\% O= 100 \% - (48.63 \% + 8.18\%)=43.19 \%%O=100%−(48.63%+8.18%)=43.19%
74g/mol∗48.63%12g/mol∗100%=2.998( 3)atoms(C)\dfrac{74g/mol*48.63\%}{12g/mol*100\%}=2.998(~3)atoms(C)12g/mol∗100%74g/mol∗48.63%=2.998( 3)atoms(C)
74g/mol∗8.18%1g/mol∗100%=6.05atoms(H)\dfrac {74g/mol*8.18\%}{1g/mol*100\%}=6.05 atoms(H)1g/mol∗100%74g/mol∗8.18%=6.05atoms(H)
74g/mol∗43.19%16g/mol∗100%\dfrac{74g/mol*43.19 \%}{16g/mol*100\%}16g/mol∗100%74g/mol∗43.19% ~ 3 atoms(O)
molecular formula of lactic acid: C3H6O3
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