As 1 dm3 = 1 l, the molarity of NaHCO3 is c = 0.1 mol/l.
Let`s convert cm3 into l.
75 cm3 = 0.075 l; 60 cm3 = 0.06 l;
Now, we will count the amount of NaHCO3.
n(NaHCO3) = c * V = 0.1 mol/l * 0.06 l = 0.006 mol.
n(CH3COOH) = n(NaHCO3) = 0.006 mol.
c(CH3COOH) = n/V = 0.006 mol / 0.075 l = 0.08 mol/l = 0.08 mol/dm3.
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