Question

Assume you add 175.0 mL of water to 125.0 mL of a 0.361 M KNO3 solution. What is the final molarity of your diluted solution?

Answer 1

$n(KNO3)=C*V=0.361M*0.125L=0.045125 moles$

$C(KNO3)=n/V=0.045125 moles/0.125L+0.175L=0.15mol/L$