Answer to Question #88821 in General Chemistry for Semaediong

Question

a vessel containing an unknown volume of argon gas in cm3 at 300f and 101kpa was inverted and placed in cold ethanol . as the gas contracted the pressure was quadrulped while the temperature reduced by one-third . what is the final volume of the gas in dm3

Answer 1

PV = nRT

T₁ = 300 ⁰F = (5/9 x (300 - 32)) + 273 = 422 K;

T₂ = 300/3 = 100 ⁰F = 311 K

P₁ = 101 kPa = 101000 Pa

P₂ = 101 kPa x 4 = 404 kPa = 404000 Pa

P₁V₁ / T₁ = P₂V₂ / T₂

101000 x V₁ / 422 = 404000 x V₂ / 311

V₂ = 0.001 x V₁