if 0.3 moles of H2O were produced how man moles of carbon dioxide would also have been produced
C2H6 + 7/2O2 -> 2CO2 + 3H2O
Solution:
n(CO2)=2/3*n(H2O);
n(CO2)=(2*0,3)/3=0,2 mol
Answer:n(CO2)=0,2 mol.
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