"NaOH+HCl \\to NaCl+H2O"
"n(NaOH)=\\dfrac{13.1g}{40g\/mol}=0.3275mol"
"n(HCl)=\\dfrac{33.2g}{36.46g\/mol}=0.9106mol"
NaOH is then the limiting reagent.
Theoretical yield"(H2O)=\\dfrac{13.1g*18g\/mol}{40g\/mol}=5.90g"
Answer: theoretical yield(H2O) = 5.90g
Comments
Leave a comment