Answer to Question #83906 in General Chemistry for t

Question #83906

How many atoms are in 2344 grams of iron, Fe?

Expert's answer

There are 6.02×1023 atoms in 56 g (1 mole) of Fe.

N = (2344×〖6.02×10〗^23)/56 = 2.52×1025 (atoms)

Answer

There are 2.52×1025 atoms in 2344 grams of iron.

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