Question

a. Calculate K_sp of Ag_2 CrO_4. Organize your answer so that your solution is logical. Make sure that your K_sp has correct significant figures.From the experiment CU = 0.00016 mol. Also 〖Ag〗_2 〖CrO〗_4 = 0.0016 mol

b) Calculate percentage error. Ag2CrO4 arrows 2Ag+ + CrO42-

Answer 1

A. Calculate Ksp of $\mathrm{Ag_2CrO_4}$. Organize your answer so that your solution is logical. Make sure that your Ksp has correct significant figures.

B. From the experiment $\mathrm{Cu} = 0.00016\mathrm{mol}$. Also $\mathrm{Ag_2CrO_4} = 0.0016\mathrm{mol}$

b) Calculate percentage error.

$$\mathrm{Ag_2CrO_4} \quad => 2\mathrm{Ag^+} \quad + \quad \mathrm{CrO_4^{2-}}$$ $$\mathrm{Ksp} = [\mathrm{Ag^+}]^2 [\mathrm{CrO_4^{2-}}] = (0.00032\mathrm{mol})^2 \times 0.0016\mathrm{mol} = 1.6 \times 10^{-11}$$ $$\mathrm{Ksp}(\mathrm{Ag_2CrO_4}) = 1.1 \times 10^{-12} \text{ at } 298\mathrm{K}$$ $$\% \text{ error} = \frac{(\text{experimental-theoretical})}{\text{theoretical}} \times 100$$ $$\% \text{ error} = \frac{(1.6 \times 10^{-11} - 1.1 \times 10^{-12})}{1.1 \times 10^{-12}} \times 100 = 14\%$$

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