Question

A container of 1 L capacity is divided into two equal compartments by a thin partition, which is filled with 6g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be
A. P
B. 2P
C. P/2
D. P/4

Answer 1

A container of 1 L capacity is divided into two equal compartments by a thin partition, which is filled with 6g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be

A. P

B. 2P

C. P/2

D. P/4

**Solution.**

The amount of hydrogen substance will be: $n(H_2) = \frac{m(H_2)}{M(H_2)} = \frac{6g}{2g/mol} = 3 \text{ moles}$.

The amount of methane will be: $n(CH_4) = \frac{m(CH_4)}{M(CH_4)} = \frac{16g}{16g/mol} = 1 \text{ mol}$.

The total number of moles of gas will be: $3 + 1 = 4$ moles.

The partial pressure of hydrogen will be: $\frac{3}{4} P$.

The partial pressure of methane will be: $\frac{1}{4} P$.

Total pressure according to Dalton's law: $P = \frac{1}{4} P + \frac{3}{4} P = P$.

**Answer:** A.

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