Question #82371

a core ring with diameter 0f 4cm and a height of 5cm, the weight of the core ring with the undisturbed soil is 120g. the weight of the core ring with soil after oven drying for 24 hours is 105g. thevolume occupied by air (Va)in the undisturbed soil sample is 16cm3. taking a particle density of the soil to be 2.65g/cm3, calculate the porosity?

Expert's answer

Question #82371, Chemistry / General Chemistry | for completion

a core ring with diameter 0f 4cm and a height of 5cm, the weight of the core ring with the undisturbed soil is 120g. the weight of the core ring with soil after oven drying for 24 hours is 105g. the volume occupied by air (Va) in the undisturbed soil sample is 16cm³. taking a particle density of the soil to be 2.65g/cm³, calculate the porosity?

Answer:


π=3.14r=4 cmh=5 cmV=π×r2×hV=3.14×16×5=251.2 cm3pv=0.9375 g/cm3pf=2.65 g/cm3P=(1−pv/pf)×100%P=(1−0.9375/2.65)×100%=64.62%\begin{array}{l} \pi = 3.14 \\ r = 4 \text{ cm} \\ h = 5 \text{ cm} \\ V = \pi \times r^2 \times h \\ V = 3.14 \times 16 \times 5 = 251.2 \text{ cm}^3 \\ p_v = 0.9375 \text{ g/cm}^3 \\ p_f = 2.65 \text{ g/cm}^3 \\ P = (1 - p_v / p_f) \times 100\% \\ P = (1 - 0.9375 / 2.65) \times 100\% = 64.62\% \end{array}


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