Question #82054

A stellar object is emitting radiation at 1420 nm. A detector is capturing 7 107 photons per second at this wavelength. h = 6.63 x 10-34 J-s. c = 2.998 x 108 m/s.

(a) What is the total energy of the photons detected in one second?


(b) What is the total energy of the photons detected in one hour?
1

Expert's answer

2019-01-09T05:15:08-0500

Question # 82054

A stellar object is emitting radiation at 1420 nm. A detector is capturing 7 107 photons per second at this wavelength. h=6.63×1034h = 6.63 \times 10^{-34} J-s. c=2.998×108c = 2.998 \times 108 m/s.

(a) What is the total energy of the photons detected in one second?

(b) What is the total energy of the photons detected in one hour?

Answer:

(a) The total energy detected by a stellar object in one second is equal to:


Es=nhcλ=71076.6310342.9981081420109=9.9481016JE_s = \frac{n * h * c}{\lambda} = \frac{7107 * 6.63 * 10^{-34} * 2.998 * 10^8}{1420 * 10^{-9}} = 9.948 * 10^{-16} \, J


(b) The total energy detected by a stellar object in one hour is equal to:


Eh=Es6060=3.5811012JE_h = E_s * 60 * 60 = 3.581 * 10^{-12} \, J


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