Question #81928

At 25 degrees celsius, for the 2A (aq) ----> B (aq) + C (aq) reaction, the equilibrium constant is 1.62. If the concentration of B (aq) was 0.373 M and the concentration of C (aq) was 0.509 M, what would be the minimum concentration of A (aq) necessary in order (in mol / L) to make this reaction spontaneous under these conditions?

Expert's answer

Answer on Question #81928, Chemistry / General Chemistry

At 25 degrees celsius, for the 2A (aq) ---> B (aq) + C (aq) reaction, the equilibrium constant is 1.62. If the concentration of B (aq) was 0.373 M and the concentration of C (aq) was 0.509 M, what would be the minimum concentration of A (aq) necessary in order (in mol / L) to make this reaction spontaneous under these conditions?

Solution

Expression for reaction quotient Q for reaction 2A (aq) ---> B (aq) + C (aq) is:


Q=[B][C][A]2Q = \frac{[B][C]}{[A]^2}


The reaction is spontaneous when Q<KcQ < K_c, i.e.:


[B][C][A]2<Kc\frac{[B][C]}{[A]^2} < K_c0.373×0.509cA2<1.62\frac{0.373 \times 0.509}{c_A^2} < 1.620.117<cA20.117 < c_A^20.342<cA0.342 < c_A


So, the reaction is spontaneous when cA>0.342c_A > 0.342 M. So, the minimum concentration of A is 0.343 M.

Answer: 0.343 M

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