Solution:
1.n=m/M;
M(Ca(NO3)2)=40+14×2+48×2=164 gram/mole;
2.n(Ca(NO3)2)=11.3/164=0.069 mol;
3.V(solution)=0.5 L
4.C=n/V;
C(Ca(NO3)2)=0.069/0.5=0.138 mol/L
Answer:C(Ca(NO3)2)=0.138 mol/L.
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