Solution:
2SO2+O2=2SO3
1.n=m/M
M(SO2)=32+2×16=64 gram/mole;
n(SO2)=17.98/64=0.281 mol;
2.n(SO2)=n(SO3)=0.281 mol;
3.m=n×M;
M(SO3)=32+16×3=80 gram/mole;
m(SO3)=0.281×80=22.48 gram;
4.η=m(practical output)/m(theoretical output)×100%;
η(SO3)=m(practical SO3)/m(theoretical SO3)×100%;
η(SO3)=18/22.48×100%=80.1%
Answer:η(SO3)=80.1%.
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