Question #78236, Chemistry / General Chemistry
The specific heat of plastic is 50 times greater than the specific heat of lead, 10 times greater than the specific heat of stone, and 1.5 times greater than the specific heat of water. If the samples of plastic, lead, stone, and water have identical masses and identical starting temperatures, and are given identical increases in energy of 1,000 J, which sample will end up with the highest temperature?
A. plastic
B. lead
C. stone
D. water
E. None of the Above
SOLUTION
Q=c∗m∗Δt,
in it Q is the heat energy, J;
c1 is the specific heat of plastic J/(g+∗C);
c2 is the specific heat of lead J/(g+lead∗C);
c3 is the specific heat of stone J/(g+∗C);
c4 is the specific heat of water J/(g+∗C);
m is the mass of the substance, g;
Δt1 is the change temperature of plastic in ∘C;
Δt2 is the change temperature of lead in ∘C;
Δt3 is the change temperature of stone in ∘C;
Δt4 is the change temperature of water in ∘C;
Δt1=Q/(c1∗m),Δt2=Q/(c2∗m),Δt3=Q/(c3∗m),Δt4=Q/(c4∗m),Δt1:Δt2:Δt3:Δt4=c1∗m1,000:c1∗m50∗1,000:c1∗m10∗1,000:c1∗m1.5∗1,000=1:50:10:1.5,Δt2>Δt3>Δt4>Δt1
the change temperature of lead is 50 times greater of plastic;
the change temperature of stone is 10 times greater of plastic;
the change temperature of water is 1.5 times greater of plastic.
Δt=tend−tstarttend=tstart+Δt,tstart1=tstart2=tstart3=tstart4
then t2end>t3end>t4end>t1end
ANSWER:B.
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