Question

A liquid has a specific heat of 2.81 J/goC, a mass of 90.0 g, and an initial temperature of 25.0 oC. What is the new temperature of the liquid if 2,350 J of energy are removed from it?

A. 1.57 oC
B. 9.30 oC
C. 15.7 oC
D. 34.3 oC
E. None of the Above

Answer 1

Answer on Question#78234 – Chemistry – General chemistry

Question:

A liquid has a specific heat of $2.81 \, \text{J/g}^\circ\text{C}$, a mass of $90.0 \, \text{g}$, and an initial temperature of 25.0 \, ^\circ\text{C}. What is the new temperature of the liquid if $2,350 \, \text{J}$ of energy are removed from it?

A. $1.57^\circ \text{C}$

B. $9.30^\circ \text{C}$

C. $15.7^\circ \text{C}$

D. $34.3^\circ \text{C}$

E. None of the Above

Solution:

The heat removed from the liquid: $Q = \mathrm{cm} \Delta T$

Where $\Delta T = T_0 - T$

$T_0$ – initial temperature

$T$ – final temperature

$$\Delta T = \frac{Q}{\mathrm{cm}} = \frac{2,350 \, \text{J}}{2.81 \, \frac{\mathrm{J}}{\mathrm{g}^\circ \text{C}} \times 90.0 \, \text{g}} = 9.29^\circ \text{C}$$ $$T = T_0 - \Delta T = 25.0^\circ \text{C} - 9.29^\circ \text{C} = 15.7^\circ \text{C}$$

Answer:

C. $15.7^\circ \text{C}$