Question #77503
The temperature of a gas is 298.0 k when the pressure is 4.00 atm. At the same volume, what is the temperature at which the pressure of the gas is 3.0 atm
Expert's answer
1 = 298 K
P1 = 4 atm
P2 = 3 atm
Gay-Lussac`s Law: P1/T1 = P2/T2
T2 = T1*P2/P1 = 298K*3atm/4atm = 223.5 K
P1 = 4 atm
P2 = 3 atm
Gay-Lussac`s Law: P1/T1 = P2/T2
T2 = T1*P2/P1 = 298K*3atm/4atm = 223.5 K
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#340153 on Dec 2023
#340153 on Dec 2023
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