How many grams of solid BaSO4 will form when Na2SO4 reacts with 25mL of 0.50 M Ba(NO3)2?
_Ba(NO3)2 + _Na2SO4 ---> _ BaSO4 + _ NaNO3
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Expert's answer
2018-05-23T06:26:29-0400
Answer: 1) Balance the reaction equation Ba(NO3)2 + Na2SO4 ---> BaSO4 + 2 NaNO3 2) Calculate number of moles of Ba(NO3)2 = 0.50 moles/L x 0.025 L = 0.0125 moles 3) Using stoichiometry calculate number of moles of BaSO4 =0.0125 moles 4) Calculate mass of BaSO4 = 0.0125 moles x 233.4 g/mole = 2.92 g BaSO4
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