Answer to Question #76779 in General Chemistry for Ross

Question

Methylbenzene(toluene), C6H5CH3, is a common paint thinner. It can be prepared from benzene, C6H6:
CH3Cl + C6H6 --> C6H5CH3 + HCl
-25g of benzene is combined with 20g of CH3Cl, in the presence of the appropriate catalyst
-Calculate the theoretical yield of toluene

Answer 1

1) Calculate moles of benzene = 25 g/ 78.1 g/mole =0.320 moles
2) Calculate moles of CH3Cl = 20 g/ 50.5 g/mole = 0.396 moles
3) Therefore, benzene is the limiting reactant. 0.320 moles of benzene will produce 0.320 moles of toluene
4) Theoretical mass of toluene = 0.320 moles x 92.14 g/mole = 29.5 g or 0.320 moles