how many grams of solute are present in 155 ML of 0.710 M KBr
1
Expert's answer
2018-04-30T07:24:14-0400
Answer: The solute in this case is KBr (the compound being dissolved to obtain the solution) Calculate moles of KBr = 0.155 L x 0.710 moles/L = 0.11 moles Mass of KBr = 0.11 moles x 119 g/mole = 13.1 g
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