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Answer to Question #76675 in General Chemistry for holly
Question #76675
how many grams of solute are present in 155 ML of 0.710 M KBr
Expert's answer
Answer:
The solute in this case is KBr (the compound being dissolved to obtain the solution)
Calculate moles of KBr = 0.155 L x 0.710 moles/L = 0.11 moles
Mass of KBr = 0.11 moles x 119 g/mole = 13.1 g
The solute in this case is KBr (the compound being dissolved to obtain the solution)
Calculate moles of KBr = 0.155 L x 0.710 moles/L = 0.11 moles
Mass of KBr = 0.11 moles x 119 g/mole = 13.1 g
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#340153 on Dec 2023
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