Answer on Question #74013, Chemistry / General Chemistry
Question:
A 1.00 g sample containing benzoic acid and gallic acid is titrated. Benzoic acid has MM=122 g/mol and has 1 acidic hydrogen. Gallic acid has MM=170 g/mol and has 1 acidic hydrogen. The acid mixture is dissolved and titrated with 0.500 M NaOH solution. To reach the endpoint in the titration a total volume of 14.7 mL of base was needed. What is the mass percent of benzoic and gallic acid?
Solution:
Amount of NaOH: 0.500 · 0.0147 = 0.00735 mol
Amount of the acidic hydrogen is the same: 0.00735 mol
“MM” of the “acid”: 1.00 / 0.00735 = 136 g/mol
Let “n” - molar part of the benzoic acid, then:
122n + 170(1-n) = 136
Solving the equation:
122n + 170 - 170n = 136
48n = 34
n = 0.71
Mass part of the benzoic acid: 0.71 · (122/170) = 0.51
Mass percent of the benzoic acid: 51%
Answer:
51% of the benzoic acid
49% of the gallic acid.
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