If 5.8 g of copper (I) sulfide decompose to copper metal and sulfur, how many grams of each
product are produced (2 answers required)?
1
Expert's answer
2018-01-19T16:05:08-0500
Reaction: Cu2S → 2 Cu + S Amount of copper (I) sulfide: 5.8 / 159.16 = 0.03644 mol Amount of copper: 2 ∙ 0.03644 = 0.07288 mol Mass of copper: 0.07288 ∙ 63.55 = 4.63 g Amount of sulfur: 0.03644 mol Mass of sulfur: 0.03644 ∙ 32.06 = 1.17 g
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