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Answer to Question #72577 in General Chemistry for David Costache
Question #72577
How many kmols are in 890 cg of sodium phosphate?
Expert's answer
n(Na3PO4)=m(Na3PO4)/M(Na3PO4),
M(Na3PO4)=164 kg/kmols
n(Na3PO4)=890/164=5,427 kmols of sodium phosphate.
M(Na3PO4)=164 kg/kmols
n(Na3PO4)=890/164=5,427 kmols of sodium phosphate.
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