A sample of magnesium carbonate is found to contain 1.39x10^24 atoms of oxygen. How much does the sample weigh?
1
Expert's answer
2017-11-28T15:28:06-0500
In 1 mole of magnesium carbonate (MgCO3) there’re 3 moles of Oxygen. Also it is known that 1 mole of substance contains 6.02×1023 particles. Find the amount of oxygen in the sample: ν = 〖1.39×10〗^24/〖6.02×10〗^23 = 2.3 (mole) Find the amount of magnesium carbonate in the sample: ν = 2.3/3 = 0.77 (mole) Find the mass of the sample (M(MgCO3) = 84 (g/mole)): m = 84×0.77 = 64.68 (g) Answer The sample weighs 64.68 g.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment