A sample of magnesium carbonate is found to contain 1.39x10^24 atoms of oxygen. How much does the sample weigh?
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Expert's answer
2017-11-28T15:28:06-0500
In 1 mole of magnesium carbonate (MgCO3) there’re 3 moles of Oxygen. Also it is known that 1 mole of substance contains 6.02×1023 particles. Find the amount of oxygen in the sample: ν = 〖1.39×10〗^24/〖6.02×10〗^23 = 2.3 (mole) Find the amount of magnesium carbonate in the sample: ν = 2.3/3 = 0.77 (mole) Find the mass of the sample (M(MgCO3) = 84 (g/mole)): m = 84×0.77 = 64.68 (g) Answer The sample weighs 64.68 g.
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