Why the reason first ionisation energy of Al is less than Mg, is because 3p in Al is further than 3s in Mg? If atomic radius decreases across the group then shouldnt 3p in Al be closer than the 3s in Mg? Thanks!
1
Expert's answer
2017-11-27T11:20:07-0500
The radius of the aluminum atom is smaller than the radius of the magnesium atom, it's true. But when filling electronic levels, there is a rule. Semi-filled (except s level) and filled sublevels are almost always more stable than other options. Therefore, the atoms of metals of the first groups easily give off electrons and acquire the configuration of an inert gas, preceding them. In the case of magnesium, when one electron is taken away, it goes into an unstable state s1. And when ionizing aluminum, it will go to the state s2, which is a filled sublevel and is more advantageous than s1 magnesium. Also, 3 aluminum electrons are shielded by a filled orbital.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment