Sea water has sodium ion concentration of 1.08 x 104 ppm. If the sodium is present in the form of dissolved NaCl, what mass of NaCl is in each liter of sea water? density of sea water is 1.05 g/mL
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Expert's answer
2017-11-14T09:16:07-0500
1.08×104 ppm Na = 1.08×104 mg Na/1000 g solution Density 1.05 g/ml = 1050 g/L 1.08×104 mg Na/1000 g solution ×1005 g/L= 1.13×104 mg Na/L 1.13×104 mg Na/L ×1 g/1000 mg = 11.3 g Na/L M(Na)=23 g/mol M(NaCl)=58.44 g/mol m(NaCl)=11.3 g Na/L×58.44 g NaCl/23.0 g Na=28.7 g Answer Mass of NaCl must be 28.7 g in each liter of sea water.
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Assignment Expert
23.03.21, 13:24
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Jade
21.03.21, 16:59
Please help me answer this A sample contains an average of 3.98 x 103
ppm sodium ion and 271 ppm sulfate ion. What is the millimolar
concentration of sulfate ion in this sample if the average density of
the solution in the sample is 1.02 g/mL?
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Please help me answer this A sample contains an average of 3.98 x 103 ppm sodium ion and 271 ppm sulfate ion. What is the millimolar concentration of sulfate ion in this sample if the average density of the solution in the sample is 1.02 g/mL?
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