For a chemical reaction SOCl2 + H2O SO2 + 2 HCl
a. Calculate the mass of water consumed by complete reaction of 3.50 x 102 g of SOCl2
b. Calculate the mass of HCl produced by the complete reaction of 3.50 x 102 g of SOCl2
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Expert's answer
2017-11-08T15:58:06-0500
n (SOCl2) = m / M = 350 g / 118.96 (g/mol) = 2.94 mol n (SOCl2) = n (H2O) = 2.94 mol m (H2O) = n * M = 2.94 mol * 18 g/mol = 52.92 g n (HCl) = 2 * n (SOCl2) = 2.94 mol * 2 = 5.88 mol m (HCl) = n * M = 5.88 mol * 36.45 g/mol = 214.32 g Answer: m (H2O) = 52.92 g m (HCl) = 214.32 g
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