Question #70533
A compound contains 59.4% carbon, 10.9% hydrogen, 13.9% nitrogen and 15.8% oxygen, by mass. Find the empirical formula of the compound.
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Expert's answer
Total percents are:
59.4+10.9+15.8+13.9=100
Atoms ratio can be calculated as
C:H:O:N=59.4/12.0107:10.9/1.0079:15.8/15.994:13.9/14.0067=4.95:10.81:0.988:0.992=5:11:1:1
Thus, empirical formula of the compound is C5H11NO
59.4+10.9+15.8+13.9=100
Atoms ratio can be calculated as
C:H:O:N=59.4/12.0107:10.9/1.0079:15.8/15.994:13.9/14.0067=4.95:10.81:0.988:0.992=5:11:1:1
Thus, empirical formula of the compound is C5H11NO
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#339914 on Dec 2023
#339914 on Dec 2023
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