Answer to Question #70509 in General Chemistry for Ma’Kayla

Question

In the replacement reaction of zinc nitrate and iron, how many grams of iron can be reacted with 226 mg of zinc nitrate?

Answer 1

The equation of the replacement reaction is:
Zn(NO3)2 + Fe  Fe(NO3)2 + Zn
That means that 1 mole of zinc nitrate reacts with 1 mole of iron.
Molar mass of Zn(NO3)2 is 189,4 g/mole.
The amount of Zn(NO3)2 is 0.226 (g) / 189.4 (g/mole) = 0.0012 (mole) (rounded)
The amount of Fe needed is 0.0012 mole as well.
Molar mass of Fe needed is 56 g/mole.
Mass of Fe needed is 0.0012 mole * 56 g/mole = 0.0672 g or 67.2 mg.