Chromium(III) is slow to react with EDTA (H4Y) and is therefore determined by back-titration. A pharmaceutical preparation containing cromium(III) is analyzed by treating a 2.63g sample with 5.00 mL of 0.0103 M EDTA. Following reaction, the unreacted EDTA is back titrated with 1.32mL of 0.0112M zinc solution. What is the percentage chromium chloride in the pharmaceutical preparation? (FW chromium chloride= 158.36 g/mol).
Cr3++ H4Y → CrY- + 4H+
Zn2+ + H4Y → ZnY2- + 4H+
The answer to the question is available in the PDF file https://www.assignmentexpert.com/https://www.assignmentexpert.com/homework-answers/chemistry-answer-67354.pdf
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment