Answer to Question #67348 in General Chemistry for Charlotte Groves

Question

you react some lactic acid with an excess of barium salt, and produce 22.0 grams of carbon dioxide at .500 atm and 0.00 degrees celsius. How many liters of carbon dioxide is this under these conditions?

Answer 1

For this task we use the ideal gas law:
PV=(m/M)RT, where
P - is the pressure of the gas, Pa. Conversion of atm to Pa: 1 atm = 101325 Pa.
V - is the volume of the gas, m3; Conversion of m3 to liters: 1 m3 = 1000 l.
m - is the mass of gas, g;
M – is the molar mass of the gas, g/mol;
R - is the universal gas constant = 8.31 J mol−1 K−1;
T - is the absolute temperature of the gas, K. Conversion of °C to K: K=°C+273.15.

Express volume from the above and convert result from m3 to liters:
V=((m/M)RT/P)*1000
Molar mass of carbon dioxide CO2 is 12.01 + (16.00 * 2) = 44.01 g/mol.
Do the calculation:
V= ((22.0g / 44.01g/mol) * 8.31 J mol−1 K−1 * (0.00+273.15) K / (0.500 * 101325) Pa) * 1000 = 22.40 liters.

Answer:
The volume of carbon dioxide is 22.40 liters.