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Answer to Question #66939 in General Chemistry for Faith
Question #66939
The rate constant for the equation
2 C2F4 → C4F8
is 0.0488 M−1
· s
−1
. We start with 0.166 mol
C2F4 in a 5.00-liter container, with no C4F8
initially present. What will be the concentration
of C2F4 after 2.00 hours ?
Answer in units of M.
2 C2F4 → C4F8
is 0.0488 M−1
· s
−1
. We start with 0.166 mol
C2F4 in a 5.00-liter container, with no C4F8
initially present. What will be the concentration
of C2F4 after 2.00 hours ?
Answer in units of M.
Expert's answer
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