Question

63.9 ml of 0.560 M sulfuric acid solution was completely neutralized by 28.3 ml of potassium hydroxide solution. What was the concentration of the potassium hydroxide?

Answer 1

Reaction of neutralization of sulfuric acid by potassium hydroxide:
H_2 SO_4+2KOH=K_2 SO_4+H_2 O
Using the Law of equivalence:
n(H_2 SO_4 )=n(KOH)
c(H_2 SO_4 )∙V(H_2 SO_4 )=c(KOH)∙V(KOH)
c(KOH)=(c(H_2 SO_4 )∙V(H_2 SO_4 ))/V(KOH) =(63.6 ml∙0.560 M)/(28.3 ml)=1.259 M
Answer: concentration of potassium hydroxide is 1.259 M.