Question #66675
I have the full atomic symbol 132Te2- and I'm having trouble figuring out the protons neutrons electrons for it. Also I have neutrons being 51 for a different problem, 37 electrons and a positive 3 charge but need help figuring out the protons for it and full atomic symbol.
Expert's answer
1. 132Te 2-
A = 132 – atomic mass
Z(p) = 52 protons (because of atomic number)
N(n) = A – Z = 132-52 = 80 Neutrons
E(e)= Z(p) = 52 electrons, but we have negative 2 charge. So we have 54
electrons.
Answer: 52 protons, 80 neutrons, 54 electrons.
2. N(n) = 51, E(e)=37, +3
Z(p) = E(e)+3 = 37+3=40 protons – atomic number
A = 40+51 = 91 – atomic mass
Zr
Answer: 40 protons, Zr.
A = 132 – atomic mass
Z(p) = 52 protons (because of atomic number)
N(n) = A – Z = 132-52 = 80 Neutrons
E(e)= Z(p) = 52 electrons, but we have negative 2 charge. So we have 54
electrons.
Answer: 52 protons, 80 neutrons, 54 electrons.
2. N(n) = 51, E(e)=37, +3
Z(p) = E(e)+3 = 37+3=40 protons – atomic number
A = 40+51 = 91 – atomic mass
Zr
Answer: 40 protons, Zr.
