What volume of O2 is required to produce 38.0 L of Carbon dioxide? Assume STP.
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Expert's answer
2017-04-21T12:33:05-0400
1. Write the balanced equation: C5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O(g) The equation shows that 8 moles of oxygen are required to produce 5 moles of carbon dioxide.
2. Convert moles to liters. 1 mole of any gas at STP has a volume of 22.4 L. So, from (1) we can say that (8 * 22.4) = 179.2 L of oxygen are required to produce (5 * 22.4) = 112.0 L of carbon dioxide. Therefore in order to produce 38.0 L of carbon dioxide we need (38.0 * 179.2) / 112.0 = 60.8 L of oxygen.
Answer: 60.8 liters of oxygen are needed to produce 38.0 liters of carbon dioxide.
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