Answer to Question #66554 in General Chemistry for sophia provost

Question #66554

What is the molarity of 9.4g of sodium hydroxide mixed in 345mL of water?

Expert's answer

C_M (NaOH)=n(NaOH)/V(solution) =((m(NaOH))/(M(NaOH)))/(V(H_2 O))=(9.4g/(40g/mol))/0.345L=0.68 mol/L=0.68 M
Answer: 0.68 M.

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